已知数列{an}满足a1=0,a2=-2,且a(n+2)=a(n+1)-an.则a2008=?
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已知数列{an}满足a1=0,a2=-2,且a(n+2)=a(n+1)-an.则a2008=?已知数列{an}满足a1=0,a2=-2,且a(n+2)=a(n+1)-an.则a2008=?已知数列{a
已知数列{an}满足a1=0,a2=-2,且a(n+2)=a(n+1)-an.则a2008=?
已知数列{an}满足a1=0,a2=-2,且a(n+2)=a(n+1)-an.则a2008=?
已知数列{an}满足a1=0,a2=-2,且a(n+2)=a(n+1)-an.则a2008=?
a(n+2)=a(n+1)-an=(an-a(n-1))-(a(n-1)-a(n-2))
=an-2a(n-1)+a(n-2)
=(a(n-1)-a(n-2))-2a(n-1)+a(n-2)
=-a(n-1)
a(n-1)=-a(n+2)
an=-a(n+3)=(-1)^2*a(n+3*2)=(-1)^k*a(n+3k)
2008/3=669.1
所以:a1=(-1)^(669)*a(1+3*669)=-a2008
a2008=-a1=0
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