x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a
来源：学生作业帮助网 编辑：六六作业网 时间：2025/01/21 21:59:48
x+y+z=12x-y+z=2x-z+y+a=90x+y+a+z=100,求xyzax+y+z=12x-y+z=2x-z+y+a=90x+y+a+z=100,求xyzax+y+z=12x-y+z=2x
x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a
x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a
x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a
x+y+z=12① x-y+z=2② x-z+y+a=90③ x+y+a+z=100④
①+②得2x+2z=14 x+z=7⑤
②+④得2x+2z+a=102⑥
⑥-⑤*2得a=88⑦
②+③得2x+a=92⑧
把⑦代入⑧中得2x=4 x=2⑨
把⑨代入⑤中得z=5⑩
把⑨⑩代入①得y=5
∴x=2,y=5,z=5,a=88
(打得好累哦)
x+y+z=12 x-y+z=2 可求得 y=5
x-z+y+a=90 x+y+a+z=100 可求得 z=5
由y=5 z=5 可知 x=2 a=88
分别记为1、2、3、4式，则
1式减2式得：2y=10，所以y=5；
4式减3式得：2z=10，所以z=5；
把y=5、z=5代入1式得x=2；
代入3式得a=88
经检验，无误，即a=88、x=2、y=5、z=5
a=88,x=2,y=z=5
(x+y-z)(x-y+z)=
用行列式的性质证明：y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是 （y+z-2x)(x-2y+z)分之（x-z)(y-z)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知：x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a
X=3z X+y+z=12 X+2y-2z=10
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少,
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值
(x+y-z)^2-(x-y+z)^2=?
(x-y-z)*( )=x^2-(y+z)^2 填空
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
3x-y+z=4,2z+3y-z=12,x+y+z=6的解