3(x²-2x-6)-3x(x-5)=0
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3(x²-2x-6)-3x(x-5)=03(x²-2x-6)-3x(x-5)=03(x²-2x-6)-3x(x-5)=03(x²-2x-6)-3x(x-5)=0
3(x²-2x-6)-3x(x-5)=0
3(x²-2x-6)-3x(x-5)=0
3(x²-2x-6)-3x(x-5)=0
3(x²-2x-6)-3x(x-5)=0
3x²-6x-18-3x²+15x=0
9x=18
x=2
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化简x(x-1)+2x(x+1)-3x(2x-5)我是这一算的,化简x(x-1)+2x(x+1)-3x(2x-5)=x²-x+2x²+2x-6x²+15x=x+2x²-6x²+15x=18x+2x²-6x²=12x²-6x²可以相减吗,还是我算的不对了?