7/x2+x+1/x2-x=0
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7/x2+x+1/x2-x=07/x2+x+1/x2-x=07/x2+x+1/x2-x=0解x吗?原式:=7/2x+1/2x=0即8/2x=0解得x=4
7/x2+x+1/x2-x=0
7/x2+x+1/x2-x=0
7/x2+x+1/x2-x=0
解x吗?
原式:=7/2x+1/2x=0
即8/2x=0 解得x=4
7/x2+x+1/x2-x=6/x2-1
7/x2+x+1/x2-x=0
x2-3x+1=0 x2/(x4-x2+1)
x2-5x+1=0则x2+x2/1
x2-3x-1=0,求①x2 1/x2;②x2-1/x2
解方程 2/(x2-x)+6/(1-x2)=7/(x2+x)x2为的平方
x2+x-6/(x2+x)+1=0怎么做
已知x2-4x+1=0,求x2/(x2)2-3x2+1
解方程4x2-4x+1=x2+6x+9 7x2-√6x-5=0
x2-4x+1=0,则x+1/x=?x2+1/x2=?
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708
7x2+44x+1=0
已知x2-2009x+1=0,求x2-2008x+2009/x2+1 (x2=x的平方)
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21x2是x的平方
已知x/x2-x+1=1/7,求x2/x4+x2+1
已知x/x2-x+1=7,求x2/x4+x2+1
7/x2+x+1/x2-1=2/x2-x解方程
x2-x-1=0,-x3+2x2+2008=