x2-x-1=0,-x3+2x2+2008=

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x2-x-1=0,-x3+2x2+2008=x2-x-1=0,-x3+2x2+2008=x2-x-1=0,-x3+2x2+2008=因为x^2-x-1=0所以x^2-x=1所以x^3-x^2=x即x^

x2-x-1=0,-x3+2x2+2008=
x2-x-1=0,-x3+2x2+2008=

x2-x-1=0,-x3+2x2+2008=
因为x^2-x-1=0
所以x^2-x=1
所以x^3-x^2=x即x^3-2x^2=0所以-x^3+2x^2=0
所以原式=0+2008=2008

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