如图所示,AB=CD,AE=DF,CE=BF,求证 AE‖DF
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如图所示,AB=CD,AE=DF,CE=BF,求证AE‖DF如图所示,AB=CD,AE=DF,CE=BF,求证AE‖DF如图所示,AB=CD,AE=DF,CE=BF,求证AE‖DF∵CE=BF∴CE-
如图所示,AB=CD,AE=DF,CE=BF,求证 AE‖DF
如图所示,AB=CD,AE=DF,CE=BF,求证 AE‖DF
如图所示,AB=CD,AE=DF,CE=BF,求证 AE‖DF
∵ CE=BF
∴ CE-EF=BF-EF
∴ AB=CD,AE=DF,CF=BE
∴ △CFD≌△ABE
∴∠EFD=∠AEF,
∴ AE//DF
△CFD全等△ABE,所以∠EFD=∠AEF,所以AE平行DF
sss证△abe全等△cdf,得到∠aeb=∠cfd,所以他们的补角相等,所以ae//cf,ae=cf 得平行四边形 所以AE‖DF
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