a/b-c/d=的推导那a/b=c/d=a-c/b-d的推导

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a/b-c/d=的推导那a/b=c/d=a-c/b-d的推导a/b-c/d=的推导那a/b=c/d=a-c/b-d的推导a/b-c/d=的推导那a/b=c/d=a-c/b-d的推导令a/b=c/d=t

a/b-c/d=的推导那a/b=c/d=a-c/b-d的推导
a/b-c/d=的推导
那a/b=c/d=a-c/b-d的推导

a/b-c/d=的推导那a/b=c/d=a-c/b-d的推导
令a/b=c/d=t(b≠d)
得(a-c)/(b-d)=(bt-dt)/(b-d)=t