4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39
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4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=394[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=394[2x+y]-5[2x-y]=32[2x+y]+10[
4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39
4[2x+y]-5[2x-y]=3
2[2x+y]+10[2x-y]=39
4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39
8x+4y-10x+5y=3 -> 9y-2x=3 得:x=1.875
4x+2y+20x-10y=39 ->24x-8y=39 y=0.75
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
x*x+2x+y*y-4y+5=0 x= y=
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39
初二上学期方程题 4x+y=5 5x+4y=63x-2y=1 2x+3y=13x-2y=7 7x+5y=32x+3y=17 2x-y=-4x+5y=6 2x+y=23x-6y=4 3x+2y=52x+y=73x-4y=53x+y=1x-2y=-1x+y=42x+3y=92x-3y=74x+5y=3x+y=20004x+6y=90003x+5y=113x-2y=42x+3y=215x-2y=5x+y=54x+3y=182x+3y=16x+4y=132x+3y=40x
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
4x+2y-5x-y
(x-4y)(2x+y)=
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
化简求值:2(x+y)(x-2y)-2x(x+y),其中x、y满足x^2+y^2-2x+4y=-5
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian