sin(a-π/3)=1/3,a属于(5π/6,4π/3),则cosa=

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sin(a-π/3)=1/3,a属于(5π/6,4π/3),则cosa=sin(a-π/3)=1/3,a属于(5π/6,4π/3),则cosa=sin(a-π/3)=1/3,a属于(5π/6,4π/3

sin(a-π/3)=1/3,a属于(5π/6,4π/3),则cosa=
sin(a-π/3)=1/3,a属于(5π/6,4π/3),则cosa=

sin(a-π/3)=1/3,a属于(5π/6,4π/3),则cosa=
π/2