2x+2y=1 3y+3z=2 z+y=-1 解三元一次方程组
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2x+2y=13y+3z=2z+y=-1解三元一次方程组2x+2y=13y+3z=2z+y=-1解三元一次方程组2x+2y=13y+3z=2z+y=-1解三元一次方程组由2x+2y=1,z+y=-1得
2x+2y=1 3y+3z=2 z+y=-1 解三元一次方程组
2x+2y=1 3y+3z=2 z+y=-1 解三元一次方程组
2x+2y=1 3y+3z=2 z+y=-1 解三元一次方程组
由2x+2y=1,z+y=-1
得z+y=2x-2y
又3y+3z=2
得x-y=1/3
所以2x+2y=1,x-y=1/3列方程组就得出x.y
z就可以得出了
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