|ab-2|-(b-1)(b-1)=0时,求1/ab+1/(a+1)(b+1)+ 1/(a+2)(b+2)+……+1/(a+1998)(b+1998)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 02:11:53
|ab-2|-(b-1)(b-1)=0时,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+1998)(b+1998)|ab-2|-(b-1)(b-1)=0时,求1/ab
|ab-2|-(b-1)(b-1)=0时,求1/ab+1/(a+1)(b+1)+ 1/(a+2)(b+2)+……+1/(a+1998)(b+1998)
|ab-2|-(b-1)(b-1)=0时,求1/ab+1/(a+1)(b+1)+ 1/(a+2)(b+2)+……+1/(a+1998)(b+1998)
|ab-2|-(b-1)(b-1)=0时,求1/ab+1/(a+1)(b+1)+ 1/(a+2)(b+2)+……+1/(a+1998)(b+1998)
题目是不是:
|ab-2|+(b-1)²=0时,求1/ab+1/(a+1)(b+1)+ 1/(a+2)(b+2)+……+1/(a+1998)(b+1998).
由于|ab-2|、(b-1)²都是非负数,所以必有:
|ab-2|=0
(b-1)²=0
解之,得:
b=1
a=2
代入欲求式,得:
1/(1×2)+1/(2×3)+1/(3×4)+……+1/(1999×2000)
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+(1/1999-1/2000)
=1-1/2000
=1999/2000
(a+b)^2- 2b-1 绝对值=0 求证ab-[2ab-3(ab-1)]
先化简后求值ab+a/b²-1+b-1/b²-2b+1其中根号b-2 +36b²+b²-12ab=0
a-b=-2,ab=-1时,(3a-4b-ab)-(2a-3b+5ab)=?
[a+b][a^2-ab+b^2]+ab-a^2-b^2为什么等于[a^2-ab-b^2][a+b-1]=0
已知a^2+4ab+b^2+a^2b^2+1=0,求a^3b+2a^2b^2+ab^3-ab的值
已知|a+b+2|+(ab-1)²=0,求2(a+b)-2[ab+(a+b)]-3[2(a+b)-3ab]的值.
已知|a+b+z|+(ab-1)^2=0,求2(a+b)-2[ab+(a+b)]-3[2(a+b)-3ab]的值
若(a+b)+|b+1|=0求5ab²-[3ab²-(4ab²-2a²b)}+2a²b
已知(a+b)的平方+|2b-1|=0,求a+b[2ab-3(ab-1)]的值 已知(a+b)的平方+|2b-1|=0,求a+b[2ab-3(ab-1)]的值
已知(3a-b+1)的绝对值+(3a-b/2)^2=0求b^2/a+b除以(b/a+b*ab/a+b)的值
已知;|3a-b+1|+(2a-b)^2=0,求b^2/a+b除(b/a-b乘ab/a+b)的值
已知;|3a-b+1|+(2a-b)^2=0,求b^2/a+b除(b/a-b乘ab/a+b)的值
已知;|3a-b+1|+(2a-b)^2=0,求b^2/a+b除(b/a-b乘ab/a+b)的值
|ab-2|+|b-1|=0 1/ab+1/(a+b)(b+1)+1/(a+2)(b+2)+''''''+1/(a+2008)(b+2008)=?
已知|ab-2|+|b-1|=0,试求:1/ab+1/(a+b)(b+1)+1/(a+2)(b+2)+.1/(a+2007)(b+2007)
已知a不等于b,且a^2/(ab+b^2)-b^2/(a^2+ab)=0,求证1/a+1/b=1/(a+b)
(a+b)²+(2b-1)=0,求2b-{2ab-3(ab-1)}
已知a不等于b,且a^2/(ab+b^2)-b^/(a^2+ab)=0,求证1/a+1/b=1/(a+b)