limx趋近于0 2cos2xsinx / 2sin4xcosx 为啥cos2x/cosx的极限等于一啊
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limx趋近于02cos2xsinx/2sin4xcosx为啥cos2x/cosx的极限等于一啊limx趋近于02cos2xsinx/2sin4xcosx为啥cos2x/cosx的极限等于一啊limx
limx趋近于0 2cos2xsinx / 2sin4xcosx 为啥cos2x/cosx的极限等于一啊
limx趋近于0 2cos2xsinx / 2sin4xcosx 为啥cos2x/cosx的极限等于一啊
limx趋近于0 2cos2xsinx / 2sin4xcosx 为啥cos2x/cosx的极限等于一啊
x→0时,直接代入就可以得出cos2x/cosx＝1
lim(x→0) cos2x/cosx=lim(x→0)[2(cosx)^2-1]/cosx
=lim(x→0)2cosx-1/cosx
=2-1=1
lim(x→0)(2cos2xsinx)/(2sin4xcosx)
=lim(x→0) (2cos2xsinx)/[2(2sin2xcos2xccosx]
=lim(x→0)sinx/[2(2sinxcosx)cosx]
=lim(x→0)1/(4(cosx)^2)
=1/4
limx趋近于0 2cos2xsinx / 2sin4xcosx 为啥cos2x/cosx的极限等于一啊
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