x=(y-5)÷2,4x+3y=65 ; x+y=11,x-y=7;3x-2y=9,x+2y=3各位哥哥姐姐们拜托了,帮我用代入消元法解这些方程,最好有步骤,
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x=(y-5)÷2,4x+3y=65;x+y=11,x-y=7;3x-2y=9,x+2y=3各位哥哥姐姐们拜托了,帮我用代入消元法解这些方程,最好有步骤,x=(y-5)÷2,4x+3y=65;x+y=
x=(y-5)÷2,4x+3y=65 ; x+y=11,x-y=7;3x-2y=9,x+2y=3各位哥哥姐姐们拜托了,帮我用代入消元法解这些方程,最好有步骤,
x=(y-5)÷2,4x+3y=65 ;
x+y=11,x-y=7;
3x-2y=9,x+2y=3
各位哥哥姐姐们拜托了,帮我用代入消元法解这些方程,最好有步骤,
x=(y-5)÷2,4x+3y=65 ; x+y=11,x-y=7;3x-2y=9,x+2y=3各位哥哥姐姐们拜托了,帮我用代入消元法解这些方程,最好有步骤,
1 4x+3y=65 4【(y-5)除以2】+3y=65 2y-10+3y=65 5y=75 y=15 x=(15-5)除以2=5
2 x+y-x+y=11-7 2y=4 y=2 x=11-2或7+2=9
3 3x-2y+x+2y=9+3 4x=12 x=3 3x-2y=9-2y x+2y=3+2y 所以y=0
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y²-y+17/4=0已知、x+y=6且xy=4(1)x²+y² (2)(x-y)² (3)x{四次方}+y{四次方}第一题没错 书上就这样写的!
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
x+2y=3(x+y)+5 3x-4y=4(x+y)-15
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
已知x-2y=2011,求[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷4x的值.
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
1.(-2a)³·b²÷(8a³b²) 2.-5x(2x²-3x+4)+4x³+15x3.(x²-2y²)(x+2y)-2xy(x-y)4.(x-y+z)(x-y-z)化简求值 [(x+y)(x-y)-(x+y)²-2y(x-2y)]÷(-2y),其中x=5,y=2003
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
先化简,再求值 [2/3x - 2/x+y(x+y/3x -x-y)]*x/x-y,其中5x+3y=0
先化简,再求值:[(x+2y)²-(x+y)(3x-y)-5y²]÷2x,其中x=-2,y=1/2
先化简,再求值:[(x+2y)²-(x+y)(3x-y)-5y²]÷2x,其中x=-2,y=1/2
先化简,再求值:[(x+2y)²-(x+y)(3x-y)-5y²]÷2x,其中x=-4,y=-3.