求不定积分∫xcos2xdx 求过程答案!谢谢!
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/19 03:08:06
求不定积分∫xcos2xdx求过程答案!谢谢!求不定积分∫xcos2xdx求过程答案!谢谢!求不定积分∫xcos2xdx求过程答案!谢谢!∫xcos2xdx=(1/2)∫xcos2xd2x=(1/2)
求不定积分∫xcos2xdx 求过程答案!谢谢!
求不定积分∫xcos2xdx 求过程答案!谢谢!
求不定积分∫xcos2xdx 求过程答案!谢谢!
∫ xcos2x dx
= (1/2)∫ xcos2x d2x
= (1/2)∫ x dsin2x
= (1/2)xsin2x - (1/2)∫ sin2x dx
= (1/2)xsin2x - (1/2)(1/2)(-cos2x) + C
= (1/2)xsin2x + (1/4)cos2x + C
∫xcos2xdx =∫x2cos2xdx/2 =(xsin2x-∫sin2xdx)/2=(xsinx-∫2sin2xdx/2)/2=xsinx/2+cos2x/4
4sinx^2-2x^2