x>=0 f(x)=ax+b；x
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x>=0f(x)=ax+b；xx>=0f(x)=ax+b；xx>=0f(x)=ax+b；xf(x)=ax+b;x>=0=arctan(1/x)+e^(1/x);x0+)f(x)=lim(x->0+)a
x>=0 f(x)=ax+b；x
x>=0 f(x)=ax+b；x
x>=0 f(x)=ax+b；x
f(x)=ax+b ; x>=0
=arctan(1/x)+e^(1/x) ; x0+)f(x)
= lim(x->0+) ax+b
= b
lim(x->0-)f(x)
= lim(x->0-)arctan(1/x)+e^(1/x)
=-π/2
f(0+)=f(0-)
=>b= -π/2
f'(0+)=a
f'(x-) = -1/[x^2(x^2+1)] -(1/x^2)e^(1/x)
f'(0-) = -[1- (x^2+1)e^(1/x)]/[x^2(x^2+1)]
f'(0+) = -1
a=-1
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x>=0 f(x)=ax+b；x
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