1.9x^2-16(x+b)^22.(x+y)^3(x-y)-(x+y)(x-y)^33.25(x-2y)^3+4(2y-x)4.81a^5b^5-ab

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1.9x^2-16(x+b)^22.(x+y)^3(x-y)-(x+y)(x-y)^33.25(x-2y)^3+4(2y-x)4.81a^5b^5-ab1.9x^2-16(x+b)^22.(x+y)^

1.9x^2-16(x+b)^22.(x+y)^3(x-y)-(x+y)(x-y)^33.25(x-2y)^3+4(2y-x)4.81a^5b^5-ab
1.9x^2-16(x+b)^2
2.(x+y)^3(x-y)-(x+y)(x-y)^3
3.25(x-2y)^3+4(2y-x)
4.81a^5b^5-ab

1.9x^2-16(x+b)^22.(x+y)^3(x-y)-(x+y)(x-y)^33.25(x-2y)^3+4(2y-x)4.81a^5b^5-ab
1.9x^2-16(x+b)^2
=(3x)^2-(4x+4b)^2
=[3x+(4x+4b)][3x-(4x+4b)]
=-(7x+4b)(x+4b)
2.(x+y)^3(x-y)-(x+y)(x-y)^3
=(x+y)(x-y)[(x+y)^2-(x-y)^2]
=(x+y)(x-y)[(x+y)+(x-y)][(x+y)-(x-y)]
=(x+y)(x-y)*2x*2y
=4xy(x+y)(x-y)
3.25(x-2y)^3+4(2y-x)
=25(x-2y)^3-4(x-2y)
=(x-2y)[25(x-2y)^2-4]
=(x-2y)[(5x-10y)^2-2^2]
=(x-2y)[(5x-10y)+2][(5x-10y)-2]
=(x-2y)(5x-10y+2)(5x-10y-2)
4.81a^5b^5-ab
=ab(81a^4b^4-1)
=ab[(9a^2b^2)^2-1]
=ab(9a^2b^2+1)(9a^2b^2-1)
=ab(9a^2b^2+1)[(3ab)^2-1]
=ab(3ab+1)(3ab-1)(9a^2b^2+1)

1.9x^2-16(x+b)^22.(x+y)^3(x-y)-(x+y)(x-y)^33.25(x-2y)^3+4(2y-x)4.81a^5b^5-ab 若多项式2x*x*x*x-3x*x*x+ax*x+7x+b能被x*x+x-2整除,求a:b a(x)/b(x)导数是[a'(x)b(x)-a(x)b'(x)]/b(x)^2//怎么推导化简下列分式:x^2+x/(x^2-1) x^2+4x/x^2+8x+16 ab^2(a-b)/a^2b-ab^2 P(X>b|x x^2-6x+5= A(x-2)(x-3)B(x-6)(x+1) 设有集合A＝{x｜x*x-[x]=2}和B={x||x| 已知A={X|X^-X-2>0}B={X|X^+4X-P 1.（x^2-3)^2+2(x^2-3)(x-3)+(x-3)^22.(x+1)(x+3)(x+5)(x+7)+153.x^2+y^2+4x+2y+34.(a^2+a+1)^2+2(a^2+a+1)(a^2+a-1)+(a^2+a-1)^25.(x^2+4)^2-16x^26.(a+b+c)^2-(a-b-c)^27.25(x-y)^2-16(x+y)^28.x^4-81x^2y^29.x^2(x-y)+y^2(y-x)10.(a-b)(x-y)+(b-a)(x+y)(乘法)11.2 已知a(x*x+x-c)+b(2x*x-x-2)=7x*x+4x+3x.求a,b,c的值因式分解：(x+y)^3(x-y)-(x+y)(x-y)^3,9x^2-16(a+b)^2 2x-3/x^2-x-A/x-1+B/x求A+B 已知集合A={x|(4x^2-16x+21)/(x^2-2x+1)>=5},B={x|x^2-ax+9 x4次方-16 x方+x-4x 相同因式是 a .x方+4 b.x方-4 c.x+2 d.x-2 300字读后感 2篇俄把格式说一下吧：《xxxx》（写题目）主要内容：x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x(写那篇文章的主要内容）思考分析：x x x 1.9a^2-2b-b^2-6a 2.x^3-4x^2-x+4 3.x^4-4x^2+4x-1 因式分解急若函数f(x)=(2b-1)x+b-1,x>0;-x²+(2-b)x,x [a'(x)b(x)-a(x)b'(x)]/b(x)^2//如何通分得到的?y(x)=a(x)/b(x)分子求导a'x/b(x),对分母求导是-a(x)b'x/b(x)^2两者通分相加[a'(x)b(x)-a(x)b'(x)]/b(x)^2