r : array[0..2] of integer; 是什么意思

r : array[0..2] of integer; 是什么意思 a rectangular game board is composed of identical squares arranged in a rectangular array of r rowsa:r^2-rb:r^2-1c:r^2d：r^2+1e:r^2+ra rectangular game board is composed of identical squares arranged in a rectangular array of r rows and r+1columns.t noip2009普及组复赛第四题的n^2解法 我只有n^3的,谁能帮我改改 程序如下：Var jiazhi,f:array[0..10000]of longint;a:array[1..10000,1..10000]of longint;n,m,p,sum,op,g,i,j,k,i2,j2:longint;Beginreadln(n,m,p);for i:=1 to n dofor j:=1 a array of quention Array of 如上 redundant array of independent Redundant Array of Inexpensive pascal dec(n,4)是神马意思?还有请解释下这个程序.const c:array[0..9]of integer=(6,2,5,5,4,5,6,3,7,6);var n,s:integer;a:array[0..1111]of integer;procedure init;var i:integer;beginreadln(n);if n main() { int i,*ptr; int array[]={2,4,6,8,10}; ptr=array; for(i=0;i a:packed array[0..101,0..101] of boolean; packed type my=recordval,l,r:longint;end;var n,i,root,a,ppool:longint;da:array[0..100010]of my;procedure print(v:longint);beginif v=0 then exit;print(da[v].l);write(da[v].val,' ');print(da[v].r);end;procedure ins(var v:longint;a:longint);beginif v=0 thenbeg 过河卒问题求修改这是我的程序var a:array[0..20,0..20] of boolean;d:array[0..20,0..20] of longint;i,j,x,y,m,n:longint;beginreadln(n,m,x,y);for i:=0 to n dofor j:=0 to m doa[i,j]:=true;a[x+2,y+1]:=false;a[x+2,y-1]:=false;a[x-2,y+1]:=false; 单词接龙 Pascalvar a:array[0..20] of string; b,c:array[0..20] of shortint; l,n:shortint; s:string; ss,max:integer;procedure link(head:string);var k,j,i:byte; s1,s2:string;begin for i:=1 to n do if c[i]=b[i] then k:=b[i]-1 else k:= 新手求指导,深度优先搜索的问题constdata:array[1..9,0..5] of longint=((4,1,2,4,5,0),(3,1,2,3,0,0),(4,2,3,5,6,0),(3,1,4,7,0,0),(5,2,4,5,6,8),(3,3,6,9,0,0),(4,4,5,7,8,0),(3,7,8,9,0,0),(4,5,6,8,9,0));vara,b:array[1..9] of longint;x,i:longint 求PASCAL 语言的解题步骤,var a,b:array[0..2] of integer; i,j,tmp:integer; begin for i := 0 to 2 do read(b[i]); for i := 0 to 2 do begin a[i] := 0; for j := 0 to i do begin inc(a[i],b[j]); inc(b[a[i] mod 3],a[j]); end; end; tmp := 1; for i := 0 解释程序（NOIP2009普及组初赛试题）vara,b:array[0..2] of integer;i,j,tmp:integer;beginfor i := 0 to 2 doread(b[i]);for i := 0 to 2 dobegina[i] := 0;for j := 0 to i dobegininc(a[i],b[j]);inc(b[a[i] mod 3],a[j]);end;end;tmp := 1;for i := 0 十进制实数转二进制的程序Program zy6;var bin:array [0..50] of 0..1;x:longint;k,i:integer;beginwriteln('read decimal data x:'); read(x);for i:=0 to 50 do bin[i]:=0;k:=0;while x>0 dobeginbin[k]:=x mod 2;x:=x div 2;k:=k+1;end;writeln('Binary: 帮忙看看下面的循环语句的含义.var OUT:array[0...100] of byte； i：byte； end_var for i：=0 to 8 do out[i]:=0； end_for