(2-x)/(x-3)=-1/(x-3)-2 两边乘x-3 2-x=-1-2(x-3) 2-x=-(2-x)/(x-3)=-1/(x-3)-2两边乘x-32-x=-1-2(x-3)2-x=-1-2x+6x=3此时分母x-3=0,是增根,应舍去.所以方程无解.我写得对么

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 00:58:14
(2-x)/(x-3)=-1/(x-3)-2两边乘x-32-x=-1-2(x-3)2-x=-(2-x)/(x-3)=-1/(x-3)-2两边乘x-32-x=-1-2(x-3)2-x=-1-2x+6x=

(2-x)/(x-3)=-1/(x-3)-2 两边乘x-3 2-x=-1-2(x-3) 2-x=-(2-x)/(x-3)=-1/(x-3)-2两边乘x-32-x=-1-2(x-3)2-x=-1-2x+6x=3此时分母x-3=0,是增根,应舍去.所以方程无解.我写得对么
(2-x)/(x-3)=-1/(x-3)-2 两边乘x-3 2-x=-1-2(x-3) 2-x=-
(2-x)/(x-3)=-1/(x-3)-2
两边乘x-3
2-x=-1-2(x-3)
2-x=-1-2x+6
x=3
此时分母x-3=0,是增根,应舍去.
所以方程无解.我写得对么

(2-x)/(x-3)=-1/(x-3)-2 两边乘x-3 2-x=-1-2(x-3) 2-x=-(2-x)/(x-3)=-1/(x-3)-2两边乘x-32-x=-1-2(x-3)2-x=-1-2x+6x=3此时分母x-3=0,是增根,应舍去.所以方程无解.我写得对么