A1=2,an-an-1=n(n≥2),求an的通项公式

已知数列｛an｝中a1=6,且an-an-1=(an-1/n)+n+1(n属于N*,n≥2）,求an an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么意思? an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 数列{an}中,a1=1,an+1/an=n/n+2,求an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 一道数学题、、数列{an}：a1=4,an=3an-1+2n-1,n≥2求an. 数列{an}满足a1=1,an=3n+2an-1(n≥2)求an 已知数列an满足a1=2,an=a(n-1)+2n,（n≥2）,求an a1=1,Sn=n^2an,求an 数列an满足a1=1,当n≥2时an²-(n+2)*an-1*an+2*n*an-1²=0 求通项公式 已知数列an中,a1=1,an/an-1=n+1/n,n大于等于2,求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an an=an-1+2的n次方+n,a1=1,an=? 已知A1=1,An=2An-1+n（n>1）,求An. 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列{an}中,a1=2,an+1=an+ln(n+1/n),求通项公式