u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/27 14:15:56
u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差u(t)=5si
u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差
u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差
u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差
110°-(-95°)=205°
所以相位差205
u(t)=5sin(314t+110°)V与i(t)=5cos(314t-95°)A的相位差
u=100sin(314t+45°)/i=10sin(314t-30°)两者相位差
求卷积s(t)=sin(t)u(t)*u(t-1)
如何根据电压电流判断电路元件U(t)=20sin(314t+30°)V,i(t)=5cos(314t+30°)A但是答案是电容呀
f(t)=u(t)sin(3t)的傅立叶变换
Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 其中0
已知2u-t=3u+2t=5,求u,t的值
已知正弦电压u=311sin 314t,当t--0.01 s时,电压的瞬时值为( ).
u=311sin (314t-45°)V 则幅值Um= ,有效值U=?角频率W=?,u=311sin (314t-45°)V 则幅值Um= ,有效值U=?角频率W=?,频率f=?,周期T=?初期¢=?
关于正弦交流电的问题e=311Sin(314T)U中314T的含义是 314°/S*T还是100π rad/S*T怎么判断
求Laplace变换求f(t)=sint•u(t-2)和f(t)=sin(t-2)u(t-2)的Laplace变换(要有步骤),
u和i的相位差怎么计算.u=-100sin(6πt+10) i=5cos(6πt-15)
z=uv+sin(t) u=e^t v=cost 求全导数dz/dt
u=311sin(314t+30.)V求有效值u和频率fou=311sin(314t+30.)V求有效值u和频率f0帮帮忙啊,在考试
已知交流电压u=311sin(314t+60°)V可知该交流电压 的有效值U=周期T=频率F=初相Y=
用Matlab实现两个信号的相求f3(t)=f1(-t)+f1(t)的程序已知f1(t)=(-t+4)[u(t)-u(t-4)],f2(t)=sin(2pit)
matlab中的t=0:0.01:5;u=sin(t);sys=tf(100,[1 5 100]);lsim(sys,u,t),想把u改为2倍的单位阶跃,怎么改?
求交流电U=U0|sinωt|,在一个周期内电压U的平均值