int a=5;b=3;cout

int a=5;b=3;cout int a=3；cout C++题目看不懂,结果是怎么算出来的,#includeusing std::cin;using std::cout;using std::endl;float f1(int);float f2(int);double twice(float (*)(int),int);int main(){int a=3;int b=5;cout int a=5,b=3,c; c=++a*--b; cout int a=5,b=7,c; c=a+++++b; cout #include void main（） { int a=1 b=2 c=3 cout int x=-5,y;cout #include using namespace std; int main() { int a,b,c; a=3; int f(int x,int y,int z);#include using namespace std; int main() {int a,b,c;a=3;int f(int x,int y,int z); cin>>a>>b>>c;c=f(a,b,c);cout int a=4,b=3,c=1,d; d=a&&b&&b>c-!0;cout #include int main() { using namespace std; int a=3,b=7,c; c=(a++,--b,a*b); cout #include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }int f2(int a,int b){ int c;a+=a;b+=b;c=f1(a+b=14,++b9);return c;}void main(){ int a=3,b=4;cout 关于变量定义的问题int a=12,b=23;cout #define MA（x） x*x-1 int a=1,b=2; cout c++中::a表示啥,看下面程序# include int a=5;void main(){ int a=3;a++;cout int main() { float a=1.0f; cout C++ 用类解决毕达哥拉斯三元组#includeusing std::cout;using std::endl;class functionBDGLS{public:functionBDGLS( int,int,int );int BDGLS( int,int,int );private:int a;int b;int c;}functionBDGLS::functionBDGLS( int ,int ,int ){int a = 0;int b struct { int i ,j ,k; } a[3]={1,2,3,4,5,6,7,8,9}; cout 英语翻译int a;std::cin>>a;int b;std::cin>>b;int value=a;int pow=b;int result =1;for (int cnt=0;cnt =pow;++cnt)result*=value;std::cout