cosπ/12=
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cosπ/12=cosπ/12=cosπ/12=(√6+√2)/4
cosπ/12=
cosπ/12=
cosπ/12=
(√6+√2)/4
cosπ/12=
cos(π/12)cos(5π/12)=
cos(π/32)*cos(π/16)*cos(π/8)=
sinπ/12*cosπ/12=?
sin(π/12)-cos(π/12)=
cos(-π/12)过程
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(sinπ/12+cosπ/12)(sinπ/12-cosπ/12)=
cos5/12πcosπ/12+cosπ/12sinπ/6=?
若x=π/12,则cos(2x-π)*cos[2(x-π)]=?
化简函数y=cos^2(x+7π/12)-cos^2(x+π/12),
已知cos(a-b)=-12/13 cos(a+b)=12/13且π/2
(sinπ/24)(cosπ/24)(cosπ/12)
(sinπ/24)(cosπ/24)(cosπ/12)
化简cos(π/12)*cos(5π/12)
cos (π/12) × cos(5×π/12)的值
化简cos(π/4-a)cos(π/4+a)=
化简cos(1-π)+cos(3π+1)=