cos(π/32)*cos(π/16)*cos(π/8)=
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/27 16:07:26
cos(π/32)*cos(π/16)*cos(π/8)=cos(π/32)*cos(π/16)*cos(π/8)=cos(π/32)*cos(π/16)*cos(π/8)=Cos[Pi/32]Cos
cos(π/32)*cos(π/16)*cos(π/8)=
cos(π/32)*cos(π/16)*cos(π/8)=
cos(π/32)*cos(π/16)*cos(π/8)=
Cos[Pi/32] Cos[Pi/16] Cos[Pi/8] = 1/(Sec[Pi/8] Sec[Pi/16] Sec[Pi/32]) = -((-1)^(25/32) (1 + (-1)^(1/16)) (1 + (-1)^(1/8)) (1 + (-1)^(1/4)))/8
cos(π/32)*cos(π/16)*cos(π/8)=
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值
根号2sinπ/32*cosπ/32*cosπ/16*cosπ/18 怎么化简
化简:cos(-π-α)
cos^3(-π-α)
计算：cos（π/5)+cos（2π/5)+cos(3π/5)+cos(4π/5)
cos(π/17)*cos(2π/17)*cos(4π/17)*cos(8π/17)
cos(-π/12)过程
cosπ/12=
cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
cos
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值：cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
怎么算cos-32π/3
大根号1-cos(π+a)cos(π-a) （π