tana=3,则(2sin^3a+cosa)/(cos^3a-sin^2a×cosa)=
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tana=3,则(2sin^3a+cosa)/(cos^3a-sin^2a×cosa)=tana=3,则(2sin^3a+cosa)/(cos^3a-sin^2a×cosa)=tana=3,则(2si
tana=3,则(2sin^3a+cosa)/(cos^3a-sin^2a×cosa)=
tana=3,则(2sin^3a+cosa)/(cos^3a-sin^2a×cosa)=
tana=3,则(2sin^3a+cosa)/(cos^3a-sin^2a×cosa)=
原式=[2tanα(sinα)^2+1]/[(cosα)^2-(sinα)^2]
=[6(sinα)^2+(cosα)^2+(sinα)^2]/[cosα)^2-(sinα)^2]
=[7(tanα)^2+1]/[1-(tanα)^2]
=(7×3^2+1)/(1-3^2)
=(63+1)/(1-9)
=-8
tana=m 则[sin(a+3pai)+cos(pai+a)]/[sin(-a)-cos(pai+a)]
若tana=1/3,则sin^3 a+2cos^ 3 a/sin^3 a-2cos^3 a
tana=2,则sin(a+3兀)+cos(兀+a)/sin(-a)-cos(兀+a)=
tana=2 则2sin^2+3cos^2a等于多少tana=2 则2sin^2a+3cos^2a等于多少
sin^2a+2sinacosa-3cos^2a= -3,则tana的值?
已知tana=2,则2sin^2a-3sinacosa+cos^2a=?
已知tana=2,则2/3(sin*2)a+1/4(cos*2)a=?
已知tana=2,则sina/sin^3a-cos^3a=
已知tana=3,则sin^2a-3sinacosa+cos^2a的值是?
已知tana=2 则2sin²a-3sinacosa-2cos²a=?
已知tana=3,则sin^2a-cos^2a=
若tana=√3 ,则cos2a-cos^2 a / sin^2 a-1=
已知tana=3,则sin^2 a-cos^ 2 a=?
已知tana=3,则sin^2a-4sinacosa+4cos^2a+1=
已知tana=2 则sin^2a +sinacosa+3cos^2a的值
若tana=-2则sin^2a-3cos^2a的值为多少
已知tanA=2,则sin²A- 3cos²A=?
若tanA=3,则 sin²A+sinAcosA+2cos²A=