微积分definite integralEvaluate the definite integral.form 0 to a/19x^37 (a^2-x^38)^1/2 dx (a > 0)
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微积分definiteintegralEvaluatethedefiniteintegral.form0toa/19x^37(a^2-x^38)^1/2dx(a>0)微积分definiteintegr
微积分definite integralEvaluate the definite integral.form 0 to a/19x^37 (a^2-x^38)^1/2 dx (a > 0)
微积分definite integral
Evaluate the definite integral.
form 0 to a/19
x^37 (a^2-x^38)^1/2 dx (a > 0)
微积分definite integralEvaluate the definite integral.form 0 to a/19x^37 (a^2-x^38)^1/2 dx (a > 0)
= From 0 to a/19 (a^2-x^38)^1/2 d x^38/38
replace x^38 with y,derives
=From 0 to (a/19)^38 (a^2-y)^1/2 d y/38
again replace (a^2-y)^1/2 with z
= 1/38 From a^2 to (a^2-(a/19)^38)^1/2 -2z^2 dz
= - 1/(3*19) From a^2 to (a^2-(a/19)^38)^1/2 d z^3
=- 1/(3*19) [a^6 - a^2-(a/19)^38)^3/2]
令u=x^38,则原式=积分（从0 到(a/19)^{38}），被积函数为
(a^2-u)^{1/2}, 其原函数为{2/3}(a^2-u)^{3/2}.代入即得结果。
感觉题目数据不对。
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