y=1-[sin(x+π/3)]^2的最小正周期是?

sin^2x+cos^2y=1/2 求3sin^2x+sin^2y的最值 y=3sin(1/2x-π/4)+1的最值和单调区间 求y=3sin(2x+π/3)的最值,及x的范围 y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)的最值 用向量解 求函数y=1/2sin(1/3x-π/6）的周期,最值 求y=1/2sin(3x+π/6)的单调区间及最值,周期 y=√3sin(1/2x-π/4) 最值 X=?Y max= 求y=sin^2x*cosx的最值? y=1-sin(2x)/sin(x)-cos(x)求T.最值 求下列函数的单调增区间,最值,x的集合 (1) y=sin(2x-π/3) (2) y=3sin(-2x+π/3) y=sin^2x+sinxcosx+3cos^2x的最值 已知x∈[π/6,π/3],求函数y=2sin²x+cosx-1的最值及对应的自变量x的值 求函数的最值!y=2-sin(x-π/4),x属于[3π/4,9π/4] 若|x|≤π/4,求函数y=2sin|x+π/3|-2sinx的最值 y=sin(2x+π/6)+cos²x-1的周期、单调区间、最值、对称轴 (1)y=2sin^2 x-cos x-1 最小值 (2)y=sinxcos(x-π/3)+sinxcosx最值 (3)y=sinxsin(π/2+x)+2sin^2x-1最值求答案阿!要具体步骤阿 y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期各是多少, y=sin(x-π/6) 和 y=1/2sin(π/3-2x) 的单增区间,