x(x-3)=2(3-x)
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x(x-3)=2(3-x)x(x-3)=2(3-x)x(x-3)=2(3-x)x(x-3)=2(3-x)x(x-3)=-2(x-3)移项得:x(x-3)+2(x-3)=0提取公因式(x-3)得:(x-
x(x-3)=2(3-x)
x(x-3)=2(3-x)
x(x-3)=2(3-x)
x(x-3)=2(3-x)
x(x-3)=-2(x-3)
移项得:x(x-3)+2(x-3)=0
提取公因式(x-3)得:(x-3)(x+2)=0
x-3=0 或 x+2=0
x1=3 x2=-2
2x-3x=6-2x
1x=2
x=1
求采纳
(X+1)X(X+2)X(X+3)=504
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
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