求值:log(√2 -1)(3+2√2)=___
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求值:log(√2-1)(3+2√2)=___求值:log(√2-1)(3+2√2)=___求值:log(√2-1)(3+2√2)=___原式=[log(√2+1)(3+2√2)]/[log(√2+1
求值:log(√2 -1)(3+2√2)=___
求值:log(√2 -1)(3+2√2)=___
求值:log(√2 -1)(3+2√2)=___
原式=[log(√2+1)(3+2√2)]/[log(√2+1)(√2-1)]
=2/[log(√2+1)(√2-1)]
1/(√2+1)=√2-1
所以log(√2+1)(√2-1)=-1
原式=-2
=log(√2 -1) (1+√2)^2
=log(1+√2) 1/(1+√2)^2
=-2
-2.230980187...........
因为3+2√2=(√2 +1）^2
√2 +1=1/(√2 -1)
所以3+2√2=(√2 -1)^(-2)
所以原式等于-2
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