a1=2,a(n+1)=-2an+3
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a1=2,a(n+1)=-2an+3a1=2,a(n+1)=-2an+3a1=2,a(n+1)=-2an+3a(n+1)=-2an+3a(n+1)-1=-2an+2=-2[an-1]∴{an-1}为等
a1=2,a(n+1)=-2an+3
a1=2,a(n+1)=-2an+3
a1=2,a(n+1)=-2an+3
a(n+1)=-2an+3
a(n+1)-1=-2an+2= -2[an-1]
∴{an-1}为等比数列,公比=-2,首项为a1-1=1
∴an-1=(-2)^(n-1)
an=(-2)^(n-1) +1
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