2×4/1+4×6/1+6×8/1+.+2006×2008/1怎么计算?过程和结果都要!- 对不起 题目写错了.........应该是这样1/2×4+1/4×6+1/6×8+......+1/2006×2008

|1/4-1/2|+|1/6-1/4|+|1/8-1/6|+```+|1/2008-1/2006| 1/2+1/4+1/6+1/8+.1/n 1+6+6+8+4+2+6+6+5+4+4+1+4+7+45 1+1/2+4+1/2+4+6+1/2+4+6+8+.+1/2+4+6+8...+20 1/2*4+1/4*6+1/6*8+1/8*10+---+1/198*200 10,1,8,1,6,2,4,6,2,（）. 1/2*4*6+1/4*6*8+1/6*8*10+.+96*98*100 1/2*4+1/4*6+1/6*8+.+1/2006*2008=(1/2*4)+(1/4*6)+(1/6*8)+..........+(1/2006*2008) 1/2*4+1/4*6+1/6*8+1/8*10.1/2006*2008 计算1/2*4+1/4*6+1/6*8+.+1/2002*2004+1/2004*2006 1+1+2+1+2+6+4+5+8等于 1/4+5/8+6/2=? 1,2,3,4,5,6,8 1×2×3×4×5×6×8 2/1+4/1+4/1+6/1+8/1+16/1+32/1=? 1,2,4,6, [2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)] 2+2+5+0+4+1+6+8+2+6