[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
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[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
a^4+1/4
=(a^2+1/2)^2-a^2
=(a^2+a+1/2)(a^2-a+1/2)
=[(a+1/2)^2+1/4][(a-1/2)^2+1/4]
根据这个式子,原式可化为：
[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
={[(2+1/2)^2+1/4][(2-1/2)^2+1/4]*[(3+1/2)^2+1/4][(3-1/2)^2+1/4]*...*[(10+1/2)^2+1/4][(10-1/2)^2+1/4]}/{[(1+1/2)^2+1/4][(1-1/2)^2+1/4]*...*[(9-1/2)^2+1/4][(9+1/2)^2+1/4]}
消去一样的式子：
比如：[(2-1/2)^2+1/4]=[(1+1/2)^2+1/4]
...
所以：
=[(10+1/2)^2+1/4]/[(1-1/2)^2+1/4]
=61
不知道中间的消去有没有错,电脑上看的晕了～
希望我的回答让你满意
孩子别懒，叫计算器来，真不知道它是干嘛吃的？