lim x趋向于pai/2 (x/cotx - pai/2cosx)
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/21 18:04:00
limx趋向于pai/2(x/cotx-pai/2cosx)limx趋向于pai/2(x/cotx-pai/2cosx) limx趋向于pai/2(x/cotx-pai/2cosx)lim(
lim x趋向于pai/2 (x/cotx - pai/2cosx)
lim x趋向于pai/2 (x/cotx - pai/2cosx)
lim x趋向于pai/2 (x/cotx - pai/2cosx)
lim (x/cotx - π/2cosx)
=lim (xsinx/cosx - π/2cosx)
=lim ([xsinx-(π/2)]/cosx) 属于0/0型,洛必塔法则
=lim ([sinx+xcosx]/(-sinx)) 代入x=π/2
=1/-1=-1
lim[(sin x)^tan x],x趋向于Pai/2
lim(sinx)^tanx (x趋向于pai/2)求极限
求极限,lim x趋向于pai/2-0 cosx的pai/2 -x次方
lim x趋向于pai/2 (x/cotx - pai/2cosx)
x趋向于0 lim(1+tanx)^1-2cot 求极限
求x趋向于pai时 lim[sin/(pai-x)]的极限
lim x趋于pai/2 (x-pai/2) cot 2x
x趋向0 lim cos(1/x),x趋向pai/2 tanx
x趋向0 lim(cot x- 1/x)=?
lim(sinx/(pai-x)=?x趋向于paipai即3.14.
lim(x趋向0)ln cot x|lnx等于?
lim x趋向0 1/x∧2— cot∧2x 求极限
微积分limlim cotx/cot(2x)x趋向于0求lim值((x+1)√(5x))/2x^2 求导
limtan(2x)tan(pai/4-x) x趋向于pai/4,求极限
求极限:(x→1) lim(1-X)tg(π/2x)tg(π/2 x)等价于pai/2x :(x→1) lim(1-X)tg(π/2x) =lim(x->1)(1-x)pai/2x =lim(x->1)pai/2x-pai/2 =pai/2-pai/2 =0上面的做法错在哪里?(x→1) lim(1-X)tg(π/2 x) =lim(1-X)*cot(π/2-π/2 x) =lim(1-X)/tan(π
lim(x趋向于0)(x*cotx-1)/(x^2)
lim(1+3x)^(2/x)x趋向于零
lim(1-2x)^1/x x趋向于0