39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.求证:∠DAE= (∠C-∠B).图:

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39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.求证:∠DAE=(∠C-∠B).

39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.求证:∠DAE= (∠C-∠B).图:
39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.
39.
已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.
求证:∠DAE= (∠C-∠B).
图:

39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.39.已知,如图6-83,△ABC中,∠C>∠B,AD⊥BC于D,AE平分∠BAC.求证:∠DAE= (∠C-∠B).图:
∠DAE=1/2∠BAC-∠1
=1/2(180-∠B-∠C)-(90-∠C)
=1/2(∠C-∠B)
你要的求证结果是错的