求f(x,y)=x^2+xy+y^2+x-y+1的极值
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求f(x,y)=x^2+xy+y^2+x-y+1的极值求f(x,y)=x^2+xy+y^2+x-y+1的极值求f(x,y)=x^2+xy+y^2+x-y+1的极值二元函数求极值f''x=2x+y+1f''
求f(x,y)=x^2+xy+y^2+x-y+1的极值
求f(x,y)=x^2+xy+y^2+x-y+1的极值
求f(x,y)=x^2+xy+y^2+x-y+1的极值
二元函数求极值
f'x=2x+y+1
f'y=x+2y-1
令2者为0解得驻点为(-1,1)
f'xx=A=2,f'xy=B=1,f'yy=C=2
AC-B^2=4-1=3>0
A>0所以有极小值
fmin=0
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