(x^2-1)(y^2-1)-4xy
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(x^2-1)(y^2-1)-4xy(x^2-1)(y^2-1)-4xy(x^2-1)(y^2-1)-4xy(x^2-1)(y^2-1)-4xy=x^2y^2-x^2-y^2-4xy+1=-(x^2+
(x^2-1)(y^2-1)-4xy
(x^2-1)(y^2-1)-4xy
(x^2-1)(y^2-1)-4xy
(x^2-1)(y^2-1)-4xy=x^2y^2-x^2-y^2-4xy+1=-(x^2+y^2+2xy)+x^2y^2-2xy+1=-(x+y)^2+(xy-1)^2=(xy-1+x+y)(xy-1-x-y)
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
1-2/x+y=xy,4y+6x=xy.求xy的解?
.(x+y-2)(x+y-2xy)+(xy-1)^2
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎
x-2xy-1+4y²
(-2xy+2x+5y)-(3xy+2y-2x)-(x+4y+xy)其中x-y=4xy=-1
若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
x-y=1,xy=2.求:(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
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x-y/x^2+xy除以xy-x^2/x^2y^2-x^4*1/x-y
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
4xy-[(x²+5xy-y²)-(3xy-1/2y)]x=3,y=-6
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
已知x y=1,xy=-3,求2xy-4x 4(y-2(xy-x))
计算3xy[2xy-x(y-2)+x-1]
化简求值x-4y/2x-7xy+3y×x-2xy-3y/2x+3xy-2y÷3x-6y/4x-4xy+y,其中:x=1999,y=-1