化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
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化简:[4xy(x-y)^-1+(xy^-1-x^-1y)/(x^-1+y^-1)]/(x+y)^2化简:[4xy(x-y)^-1+(xy^-1-x^-1y)/(x^-1+y^-1)]/(x+y)^2
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
=[4xy/(x-y)+(x/y-y/x)/(1/x+1/y)]/(x+y)^2
=[4xy/(x-y)+((x^2-y^2)/xy)/((x+y)/xy)]/(x+y)^2
=[4xy/(x-y)+(x-y)]/(x+y)^2
=[(4xy+(x-y)^2)/(x-y)]/(x+y)^2
=[(x^2+2xy+y^2)/(x-y)]/(x+y)^2
=[(x+y)^2/(x-y)]/(x+y)^2
=1/(x-y)
[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
=[4xy/(x-y)+(x/y-y/x)/(1/x+1/y)]/(x+y)^2
=[4xy/(x-y)+((x^2-y^2)/xy)/((x+y)/xy)]/(x+y)^2
=[4xy/(x-y)+(x-y)]/(x+y)^2
=[(4xy+(x-y)^2)/(x-y)]/(x+y)^2
=[(x^2+2xy+y^2)/(x-y)]/(x+y)^2
=[(x+y)^2/(x-y)]/(x+y)^2
=1/(x-y)
化简4xy-y-xy+x
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
化简xy-1-x+y
化简[x-y+4xy/(x-y)][x+y-4xy/(x-y)]
化简:(x+y-4xy/x+y)*(x-y-4xy/x-y)=
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy]
xy-1+x-y
化简2(x²y+xy)-3(x²y-xy)-4x²y
化简3（x²y+xy)-4(x²y-xy)-5x²y,
x-y/x^2+xy除以xy-x^2/x^2y^2-x^4*1/x-y
化简1-x-y/x+2y÷x^2-y^2/x^2+4xy+4y^2
化简1— x-y/x+2y÷x²-y²/x²+4xy+4y²
化简(2x+y)^2-(2x-y)(2x+y)-4xy其中x=2010,y=-1
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
已知xy>0,证明xy+xy/1+x/y+y/x>=4
1-2/x+y=xy,4y+6x=xy.求xy的解?
xy>0,证xy+1/xy+x/y+y/x>=4