1-x^2+4xy-4y^2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/28 20:58:49
1-x^2+4xy-4y^21-x^2+4xy-4y^21-x^2+4xy-4y^2原式=1-(x²-4xy+4y²)=1-(x-2y)²=(1+x-2y)(1-x+2y
1-x^2+4xy-4y^2
1-x^2+4xy-4y^2
1-x^2+4xy-4y^2
原式=1-(x²-4xy+4y²)
=1-(x-2y)²
=(1+x-2y)(1-x+2y)
3(x-3)+10(2/3+y)=13
22(x-3)+5(2/3+y)=27
令a=x-3,b=2/3+y
则3a+10b=13 (1)
22a+5b=27 (2)
(1)-2*(2)
3a+10b-44a-10b=13-27*2
-41a=-41
a=1,
代入(2)
22+5b=27
b=1
所以...
全部展开
3(x-3)+10(2/3+y)=13
22(x-3)+5(2/3+y)=27
令a=x-3,b=2/3+y
则3a+10b=13 (1)
22a+5b=27 (2)
(1)-2*(2)
3a+10b-44a-10b=13-27*2
-41a=-41
a=1,
代入(2)
22+5b=27
b=1
所以x=a+3=4
y=b-2/3=1/3 3(x-3)+10(2/3+y)=13
22(x-3)+5(2/3+y)=27
令a=x-3,b=2/3+y
则3a+10b=13 (1)
22a+5b=27 (2)
(1)-2*(2)
3a+10b-44a-10b=13-27*2
-41a=-41
a=1,
代入(2)
22+5b=27
b=1
所以x=a+3=4
y=b-2/3=1/3
收起
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
1-2/x+y=xy,4y+6x=xy.求xy的解?
(x^2+2xy+y^2-4xy)*(x^2-2xy+y^2+4xy)
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎
x-2xy-1+4y²
(-2xy+2x+5y)-(3xy+2y-2x)-(x+4y+xy)其中x-y=4xy=-1
若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=
x-y=1,xy=2.求:(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
.已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
x-y/x^2+xy除以xy-x^2/x^2y^2-x^4*1/x-y
化简:[4xy(x-y)^-1 + (xy^-1 - x^-1y)/(x^-1 + y^-1)] / (x+y)^2
4xy-[(x²+5xy-y²)-(3xy-1/2y)]x=3,y=-6
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
已知x y=1,xy=-3,求2xy-4x 4(y-2(xy-x))
化简:3x^2-[5xy-(x^y-3xy)+4x^2y-8xy]