∫(x^2+1)^2dx

来源：学生作业帮助网编辑：六六作业网时间：2024/12/20 06:08:10

∫(x^2+1)^2dx∫(x^2+1)^2dx∫(x^2+1)^2dx∫(x^2+1)^2dx=∫(x^4+2x^2+1)dx=(1/5)x^5+(2/3)x^3+x+C

∫(x^2+1)^2dx
∫(x^2+1)^2dx

∫(x^2+1)^2dx
∫ (x^2 + 1)^2 dx
= ∫ (x^4 + 2x^2 + 1) dx
= (1/5)x^5 + (2/3)x^3 + x + C

∫[dx/(e^x(1+e^2x)]dx ∫(x-1)^2dx, ∫x^1/2dx ∫dx/x^2(1-x^2) ∫dx/x^2(1+x^2) ∫X^2/1-x^2 dx. ∫X^2/1-x^2 dx. ∫1/x^2+x+1dx ∫1/(x^2+x+1)dx ∫ (x+arctanx)/(1+x^2) dx ∫（x^2+1/x^4)dx ∫2 -1|x²-x|dx ∫x^2/1+X dx. ∫ xe^x/(1+x)^2 dx ∫dx/[(1-x)x^2] ∫ x/(1+X^2)dx= ∫(2x)/(1+x²)dx ∫x^3/1+x^2 dx