求证sin(a+b)cos(a–b)=sinacosb+sinbcosb

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/27 15:07:16
求证sin(a+b)cos(a–b)=sinacosb+sinbcosb求证sin(a+b)cos(a–b)=sinacosb+sinbcosb求证sin(a+b)cos(a–b)=sinacosb+

求证sin(a+b)cos(a–b)=sinacosb+sinbcosb
求证sin(a+b)cos(a–b)=sinacosb+sinbcosb

求证sin(a+b)cos(a–b)=sinacosb+sinbcosb
好难呀

展开不就得了啊!

sin(a+b)cos(a–b)
=(sinacosb+cosasinb)(cosacosb+sinasinb)
=sinacosacos^2 b +sin^2 a sinbcosb +cos^2 a sinbcosb +sinacosasin^2 b
=sinacosa(1-sin^2 b) +(1-cos^2 a)sinbcosb +cos^2 a sinbcosb +...

全部展开

sin(a+b)cos(a–b)
=(sinacosb+cosasinb)(cosacosb+sinasinb)
=sinacosacos^2 b +sin^2 a sinbcosb +cos^2 a sinbcosb +sinacosasin^2 b
=sinacosa(1-sin^2 b) +(1-cos^2 a)sinbcosb +cos^2 a sinbcosb +sinacosasin^2 b
=sinacosa-sinacosasin^2 b +sinbcosb-cos^2 a sinbcosb+cos^2 a sinbcosb +sinacosasin^2 b
=sinacosa+sinbcosb

收起

sin(a+b)cos(a-b)=(sinna+sinb)(cosa-conb)