lim(x+e^x)^1/x在x趋向于0时的值等多少啊?希望能给出详细的解法好像答案是e^2呀

lim(1+e^1/x)^x,x趋向于+0 求lim x趋向于0(e^x-x-1) 求lim x趋向于0(e^x-x-1)/x(e^x-1) lim ln(1+2x)/e^x x趋向于0 e^x lim(x趋向于0)e^sinx/x lim(x趋向于无穷大时)e^(1/x) lim x趋向于0 [ln(1+x)/x]^[1/(e^x-1)] 求极限lim[e^xsinx-x(1+x)]/x^3 其中X趋向于0 lim(x趋向于e)lnx = x趋向0 lim [ ln (1-x) / (e ^ x-1 ) ] 求极限lim （e^x）- (e^-x) -2x / (tanx-x) x趋向于0 lim(1-2x)^1/x x趋向于0 x趋向于0 lim loga(1+x)/x= lim(x趋向于0)(x*cotx-1)/(x^2) lim(1+3x)^3/x x趋向于0 lim(x趋向0）(e^x-x^-x)/x lim趋向0时,e^x-e^-1/X lim(x趋向0）(e^x-e^-x)/x