ab^2(x-y)^(m-1)=a^2b(x-y )^(m+1)=ab(x-y)^(m-1)_就是ab(x-y)^(m-1)乘多少等于^a^2b(x-y )^(m+1)等于ab^2(x-y)^(m-1)

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ab^2(x-y)^(m-1)=a^2b(x-y)^(m+1)=ab(x-y)^(m-1)_就是ab(x-y)^(m-1)乘多少等于^a^2b(x-y)^(m+1)等于ab^2(x-y)^(m-1)a

ab^2(x-y)^(m-1)=a^2b(x-y )^(m+1)=ab(x-y)^(m-1)_就是ab(x-y)^(m-1)乘多少等于^a^2b(x-y )^(m+1)等于ab^2(x-y)^(m-1)
ab^2(x-y)^(m-1)=a^2b(x-y )^(m+1)=ab(x-y)^(m-1)_
就是ab(x-y)^(m-1)乘多少等于^a^2b(x-y )^(m+1)等于ab^2(x-y)^(m-1)

ab^2(x-y)^(m-1)=a^2b(x-y )^(m+1)=ab(x-y)^(m-1)_就是ab(x-y)^(m-1)乘多少等于^a^2b(x-y )^(m+1)等于ab^2(x-y)^(m-1)
题目不太清晰,

ab^2(x-y)^m+a^2b(x-y)^m+1-ab(x-y)^m因式分解哈 ab^2(x-y)^m+a^2b(x-y)^m+1 ab^2(x-y)^(m-1)=a^2b(x-y )^(m+1)=ab(x-y)^(m-1)_就是ab(x-y)^(m-1)乘多少等于^a^2b(x-y )^(m+1)等于ab^2(x-y)^(m-1) 若抛物线 y=mx2-(m-2)x-1交x轴于A(a,0)、B(b,0)两点,且a+b=ab,则m= 分解因式3ab^2(x-y)^m-1-6a^2b(x-y)^m分解因式3ab^2·(x-y)^m-1·-6a^2·b(x-y)^m 将多项式2ab^2(x-y)^m+1-6a^2b(x-y)^m因式分解为 初一因式分解练习题,谁好心帮我解下表示平方1.2X~-3XY-X2.(X+Y)~(X+Y)(X-Y)(X+Y)(Y+Z)3.3X(a+2b)~-6XY(a+2b)4.a(x-y)-b(X-Y)-C(Y-X)5.(b-a)~-2a+2b6.(x-y)~-m(y-x)+y-x7.x(x-y)(a-b)-y(y-x)(b-a)8.已知a+b=13,ab=40,求 b+ab~的值 一、(2x-3)^2=(x+1)^2 解方程 二、[a^2b(x-y)-ab(y-x)]÷ab(a+1) 计算 三.m^2(a-b)+4n^2(b-a) 因式分解 已知抛物线y=x平方+(m-1)x+(m-2)交x轴于A,B两点,且线段AB=2,则m的值为... 已知抛物线y=x的平方+(m-1)x+(m-2)与x轴相交与A.B两点,且AB=2,则m是多少? y=x的平方加(m-1)x+(m-2)与x轴交A,B两点,且线段AB等于2,求M的值 1.设M=x+y N=x-y,则(M+N/M-N)-(M-N/M+N)等于( )A.1 B.X2-Y2/xy C.X2-Y2/2xy D.X2-Y2/xy2.如果x.y和y-1/x都不为0,则(x-1/y)/(y-1/x)等于 A.x/y b.y/x C.x/y-y/x D.xy-1/xy3.设a-b+ab=0,其中ab不等于0,则1/a-1/b=() A.1 B.2 C.1/ab D.1/a-b 已知直线y=1/2x与双曲线x²-y²=m交于A、B两点,且|AB|=2,求m的值 y=x+m与椭圆x^2/4 + y^2=1相交于A,B两点,当m变化时,求AB的最大值 (1)x的平方-y的平方+x+y(2)3x(a-b)+2y(b-a)(3)x(m-x)(m-y)-m(x-m)(y-m)(4)(2a+b)(2a-3b)+(2a+5b)(2a+b)(5)3x(a-b)-2y(b-a)(6)4p(1-q)的三次方+2(q-1)的平方(7)ab的平方(x-y)的m次方+2a的平方b x^2-y^2 x^2-2xy+y^2的公因式是 因式分解:-10x^3-6x^2+2x=m(a-b)^3+n(b-a)^2=4x^2-9y^2=(a+b)^2-4(a-b)^2=(a-b)(a^2-ab+b^2)-ab(b-a)=(a-b)(a^2-ab+b^2)+ab(b-a)=(a+b)^2-81(a-b)^2=-a^2-18a-81=-1+81x^4=因式分解(这三到要过程)x(x+y)(x-y)-x(x 分解因式;1、m(x-y)²-x+y2、(a-b)²-3a+3b3、x²(x+y)(y-x)-xy(x+y)(x-y)4、已知a+b=2,ab=-1/2,求a(a+b)(a-b)-a(a+b)² 2x+y=0,求4x²+2xy(x+y)+y³若m²+m-1=0 求m³+2m²+2011已知(a²+b²-2)(a²+b²)-35=0,a-b=1求a+b ,ab,(b²/a)+(a²/b)