数学有理数的四则混合运算题目如下,Thanks...1)-20÷5×1/4+5×(-3)/152)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/43)-3×[-5+(1-0.2÷3/5)÷(-2)]4)对1,2,3,4可作运算(1+2+3)×4=24,现有有理数3,4,-6
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数学有理数的四则混合运算题目如下,Thanks...1)-20÷5×1/4+5×(-3)/152)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/43)-3×[-5+(1-0.2÷3/5)÷(-2)]4)对1,2,3,4可作运算(1+2+3)×4=24,现有有理数3,4,-6
数学有理数的四则混合运算题目如下,Thanks...
1)-20÷5×1/4+5×(-3)/15
2)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/4
3)-3×[-5+(1-0.2÷3/5)÷(-2)]
4)对1,2,3,4可作运算(1+2+3)×4=24,现有有理数3,4,-6,10,请运用加,减,乘,除法则写出三种不同的计算算式,使其结果为24.
(1)___________
(2)___________
(3)___________
数学有理数的四则混合运算题目如下,Thanks...1)-20÷5×1/4+5×(-3)/152)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/43)-3×[-5+(1-0.2÷3/5)÷(-2)]4)对1,2,3,4可作运算(1+2+3)×4=24,现有有理数3,4,-6
1)-20÷5×1/4+5×(-3)/15=-1+(-1)=-2
2)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/4=-1/114-1=-115/114
3)-3×[-5+(1-0.2÷3/5)÷(-2)]=-3×[-5+(-1/3)]=16/9
4)三种不同的计算算式:
(1) 3 × (4 - 6 + 10)=24
(2)3 × (4 - (-6+ 10))=24
(3)3 × (4 + 10 - 6)=24
(4)10- 3 × (-6)- 4=24
前3个还简单吧,没看错的话应该是—2,—25/19,16,第四个嘛,我想了三个希望能帮到你哦
(1):3x(4+10-6)=24
(2):4-(-6)x10/3=24
(3):(10-4)x3-(-6)=24
1) =-4*1/4+-15/15=1-1=0
2) =[1/24÷(-5/4)×(-5/6)÷(-19/6)]-1/4×4=[-5/36×6/19]-1=-5/114-1=-119/114
3)=-3×[-5+(1-1/3)/(-2)]=-3×[-5+2/3×(-2)]=-3×[-19/3]=19
4)3×(4-6+10)=24
)-20÷5×1/4+5×(-3)/15
=-4×1/4-1
=-1-1
=-2
2)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/4
=[1/24÷(-5/4)×(-5/6)÷(-19/6)]-0.25÷1/4
=[1/24×(-4/5)×(-5/6)×(-6/19)]-0.25÷1/4
=-1/114-1<...
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)-20÷5×1/4+5×(-3)/15
=-4×1/4-1
=-1-1
=-2
2)[1/24÷(-1又1/4)×(-5/6)÷(-3又1/6)]-0.25÷1/4
=[1/24÷(-5/4)×(-5/6)÷(-19/6)]-0.25÷1/4
=[1/24×(-4/5)×(-5/6)×(-6/19)]-0.25÷1/4
=-1/114-1
=-1又1/114
3)-3×[-5+(1-0.2÷3/5)÷(-2)]
=-3×[-5+(1-1/5×5/3)×(-1/2)]
=-3×[-5+(1-1/3)×(-1/2)]
=-3×[-5+2/3×(-1/2)]
=-3×[-5-1/3)]
=-3×(-16/3)
=16
4)3×(4-6+10)=24
10-4- 3×(-6)=24
4-(-6)×10÷3=24
收起
1) =-4*1/4+-15/15=1-1=0
2) =[1/24÷(-5/4)×(-5/6)÷(-19/6)]-1/4×4=[-5/36×6/19]-1=-5/114-1=-119/114
3)=-3×[-5+(1-1/3)/(-2)]=-3×[-5+2/3×(-2)]=-3×[-19/3]=19
4)3×(4-6+10)=24 1):3x(4+10-6)=24