cos（5π/8）*cosπ/8
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/17 04:26:31
cos（5π/8）*cosπ/8cos（5π/8）*cosπ/8cos（5π/8）*cosπ/8cos（5π/8）*cos（π/8）=-sin（π/8）*cos（π/8）又∵sin（π/4）=2sin
cos（5π/8）*cosπ/8
cos（5π/8）*cosπ/8
cos（5π/8）*cosπ/8
cos（5π/8）*cos（π/8）=-sin（π/8）*cos（π/8）
又∵sin（π/4）=2sin（π/8）*cos（π/8）
∴cos（5π/8）*cos（π/8）=-sin（π/8）*cos（π/8）=-1/2（sin（π/4））
最后的答案应该是
负的四分之根号二
cos（5π/8）*cosπ/8
cos(π/32)*cos(π/16)*cos(π/8)=
cos(5π/8)*cos（π/8)=
化简cos^8(π/8)+cos^8(3π/8)+cos^8(5π/8)+cos^8(7π/8)
cos^2 π/8+cos ^2 3π/8+ cos^2 5π/8+cos^2 7π/8=?
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
cos(π/17)*cos(2π/17)*cos(4π/17)*cos(8π/17)
化简cos（π/12）*cos（5π/12）
cos（-8π/3）求值
cos（-8π/3）求值
cos²（π/8）-0.5=
函数 (4 20:28:50)cos^4 (π /8)+cos^4(3π/8)+cos^4(5π/8)+cos^4(7π/8) =
不用计算器,求(cos(π/8))^4+(cos(3π/8))^4+(cos(5π/8))^4+(cos(7π/8))^4的值
0.5-cos^2(π/8)
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
COS(π/17)COS(2π/17)COS(4π/17)COS(8π/17)要过程
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a）
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值