a(n+2)=(2+i^2n)an+1+i^2n,求an

a(n+2)=(2+i^2n)an+1+i^2n,求an 对于数列A(n),极限（2n-1)An=1,求极限 n*A(n) a1=1,a(n+1)=2an+n^2+2n +2 求an 已知a1=2 a(n+1)=2an+2^n+3^n 求an A1=1,A(n+1)/An=(n+2)/n,求An? 周期性数列问题i已知数列｛an}满足a(n+1)=2an (0 a(n+1)=2an+2^n-1. an-a(n-1)=2n-10 求通项公式 a(n+1)=an+2n怎样用待定系数法求通项 设bn=(n-1)/(an-2),(n大于等于2),an=n^a-n+2,且b(n+1)+b(n+2)+...b(2n+1) 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列{an},a1=3,an*a(n+1)=(1/2)^n,求an 已知数列｛an｝中,a(n+1)=an+2^n,a1=3,求an 数列an中,若a（ n+1）=an+(2n-1)求an 已知数列{an}满足a1=1,且an=1/3a(n-1)+(1/3)^n (n≥2,且n∈N+),则数列{an}的通项公式为A.an=3^n/(n+2) B.an=(n+2)/3^n C.an=n+2 D.an=(n+2)3^n 已知a1=3,a(n+1)=(3n-1)/(3n+2)an(n≥1),求an An>0,A1=2,当n>=2,An+A(n-1)=n/(An-A(n-1))+2,求An通项 An>0,A1=2,当n>=2,An+A(n-1)=n/(An-A(n-1))+2,求An通项