计算:2^n+4-2x2^n除以2x2^n+3

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计算:2^n+4-2x2^n除以2x2^n+3计算:2^n+4-2x2^n除以2x2^n+3计算:2^n+4-2x2^n除以2x2^n+32^n+4-2x2^n除以2x2^n+3=[2^(n+4)-2

计算:2^n+4-2x2^n除以2x2^n+3
计算:2^n+4-2x2^n除以2x2^n+3

计算:2^n+4-2x2^n除以2x2^n+3
2^n+4-2x2^n除以2x2^n+3
=[2^(n+4)-2^(n-1)]÷2^(n+4)
=1-2^(n-1-n-4)
=1-2^(-5)
=1-1/32
=31/32