计算:2^n+4-2x2^n除以2x2^n+3
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计算:2^n+4-2x2^n除以2x2^n+3计算:2^n+4-2x2^n除以2x2^n+3计算:2^n+4-2x2^n除以2x2^n+32^n+4-2x2^n除以2x2^n+3=[2^(n+4)-2
计算:2^n+4-2x2^n除以2x2^n+3
计算:2^n+4-2x2^n除以2x2^n+3
计算:2^n+4-2x2^n除以2x2^n+3
2^n+4-2x2^n除以2x2^n+3
=[2^(n+4)-2^(n-1)]÷2^(n+4)
=1-2^(n-1-n-4)
=1-2^(-5)
=1-1/32
=31/32
计算:2^n+4-2x2^n除以2x2^n+3
化简2^n+4 -2x2^n除以2x2^n+3得______(麻烦了哈,n_n)
(2的n 4次方-2x2的n次方)除以(2x2的n-3次方)
Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n sn=2sn-sn我想知道2SN等于多于.尤其是(2n-1)x2^n 除以2等于多少.
1+2x2+3x2^2+4x2^3+.+nx2^n-1=?
1+2x2+3x2^2+4x2^3+.+nx2^n-1=?
Sn=1x2+3x2^2+5x2^3+...+(2n-1)2^n
1x2+2x3+3x4+4x5+.+n(n+1)+n(n+2)=?
求和Sn=1x2+3x2^2+5x2^3+…+(2n-1)x2^n
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