If f(x)=4x+1 and g(x)=x^2-3x+1,then (f+g)(-2)=?

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Iff(x)=4x+1andg(x)=x^2-3x+1,then(f+g)(-2)=?Iff(x)=4x+1andg(x)=x^2-3x+1,then(f+g)(-2)=?Iff(x)=4x+1and

If f(x)=4x+1 and g(x)=x^2-3x+1,then (f+g)(-2)=?
If f(x)=4x+1 and g(x)=x^2-3x+1,then (f+g)(-2)=?

If f(x)=4x+1 and g(x)=x^2-3x+1,then (f+g)(-2)=?
f(x)=4x+1,g(x)=x^2-3x+1
f(x)+g(x)=x^2+x+2
f(-2)+g(-2)=4-2+2=4