若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=

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若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π

若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=
若cos31°=α,则sin211°=
若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=
若cos(π+α)=-1/2,则cos(2π-α)=
若tan(α-π)=k,则tan(π+α)=

若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=
(1)因为,sin(x+π)=-sinx, sin(x+2π)= sinx
而且 sin(-x)=-sinx
sin(π-4)+sin(π+4)+sin(2π-4)
= m - m - m
= - m;
(2)类似, cos(-x)=cosx
cos(2π-α)= cos(-2π+α)= - cos(π+α)=1/2;
(3)若tan(α+π)= tan(π+α-2π)= tan(α-π)=k.