若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=
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若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π
若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=
若cos31°=α,则sin211°=
若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=
若cos(π+α)=-1/2,则cos(2π-α)=
若tan(α-π)=k,则tan(π+α)=
若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=
(1)因为,sin(x+π)=-sinx, sin(x+2π)= sinx
而且 sin(-x)=-sinx
sin(π-4)+sin(π+4)+sin(2π-4)
= m - m - m
= - m;
(2)类似, cos(-x)=cosx
cos(2π-α)= cos(-2π+α)= - cos(π+α)=1/2;
(3)若tan(α+π)= tan(π+α-2π)= tan(α-π)=k.
若cos31°=α,则sin211°=若sin4=m,则sin(π-4)+sin(π+4)+sin(2π-4)=若cos(π+α)=-1/2,则cos(2π-α)=若tan(α-π)=k,则tan(π+α)=
cos31°=a则sin239°tan149°=
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cos14°cos31°-sin14°sin31°=?
已知cos31=a sin239°tan149°
已知cos31°=m,则sin239°·tan149°的值是_________
1.cos31°=a,则sin239°×tan149°=_________2.已知sin(pie / 6—a)=m,则cos(2÷3×pie—a)=________3.若f(sinx)=cos2x,则f(cosx)=__________
已知cos31度=m,则sin239度*tan149度等于
已知cos31度=m,则sin239度tan149度的值为?
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