解方程组:1'(x+y)^2=4 2'(x-y)^2=1
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解方程组:1''(x+y)^2=42''(x-y)^2=1解方程组:1''(x+y)^2=42''(x-y)^2=1解方程组:1''(x+y)^2=42''(x-y)^2=1由题可以得出以下四组二元一次方程组:一
解方程组:1'(x+y)^2=4 2'(x-y)^2=1
解方程组:1'(x+y)^2=4 2'(x-y)^2=1
解方程组:1'(x+y)^2=4 2'(x-y)^2=1
由题可以得出以下四组二元一次方程组:
一:x+y=2、x-y=1 ===>x=1.5、y=0.5
二:x+y=2、x-y=-1 ===>x=0.5、y=1.5
三:x+y=-2、x-y=1 ===>x=-0.5、y=-1.5
四:x+y=-2、x-y=-1 ===>x=-1.5、y=-0.5
' 是什么意思
把乘除号打清楚啊 看不懂
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