已知f(x)=ax^+bcosx+sinx-1,满足f(π/6)=5,则f(-π/6)等于( )A.5 B.-5 C.4 D.-4

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已知f(x)=ax^+bcosx+sinx-1,满足f(π/6)=5,则f(-π/6)等于()A.5B.-5C.4D.-4已知f(x)=ax^+bcosx+sinx-1,满足f(π/6)=5,则f(-

已知f(x)=ax^+bcosx+sinx-1,满足f(π/6)=5,则f(-π/6)等于( )A.5 B.-5 C.4 D.-4
已知f(x)=ax^+bcosx+sinx-1,满足f(π/6)=5,则f(-π/6)等于( )
A.5 B.-5 C.4 D.-4

已知f(x)=ax^+bcosx+sinx-1,满足f(π/6)=5,则f(-π/6)等于( )A.5 B.-5 C.4 D.-4
C ax^+bcosx部分,π/6与-π/6的函数值相等,均为5.5(用f(π/6)=5算出).再套入第二个式子便可得出答案.