102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y)^5 求y=?
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102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y)^5求y=?102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+1
102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y)^5 求y=?
102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y)^5 求y=?
102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y)^5 求y=?
从而求得Y=7.4% 假如你要问我为什么当初用插值法的时候选7%和8%这两个数,我也说不好,一开始我用10%算的,希望对你有用.当然这个还要期待高手来
我不会算希望能有解答过程
y (3y^2+8y-3)-6y(3y+2y-1)+9y
3（3+y)-8y=14 y=-1
y-2[y-4(y-1)]-8=0
y- 2y+1/2=9- 8-y/4
y-2y+1/2=9-8-y/4
102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y)^5 求y=?
8y-1=4y² 】
2y+8y-1=0
y^+3y-1=0,求y^4/^8-3y^4+1的值
x+(9-8-y)=10 y+y-(9-8-y)=2 x-y=xx-9.9x xy=11y-1 y=? x=? x+y-xy=?x+(9-8-y)=10y+y-(9-8-y)=2x-y=xx-9.9xxy=11y-1 y=?x=?x+y-xy=?
急,看不懂问我(y+3)^2/8-y=(y+3)/4-(y-1)/2
[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.')
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